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Code d'Examen: 312-49
Nom d'Examen: EC-COUNCIL (Computer Hacking Forensic Investigator )
Questions et réponses: 150 Q&As
312-49 Démo gratuit à télécharger: http://www.pass4test.fr/312-49.html
NO.1 The newer Macintosh Operating System is based on:
A. OS/2
B. BSD Unix
C. Linux
D. Microsoft Windows
Answer: B
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NO.2 In a computer forensics investigation, what describes the route that evidence takes from the time
you find it until the case is closed or goes to court?
A. rules of evidence
B. law of probability
C. chain of custody
D. policy of separation
Answer: C
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NO.3 In the context of file deletion process, which of the following statement holds true?
A. When files are deleted, the data is overwritten and the cluster marked as available
B. The longer a disk is in use, the less likely it is that deleted files will be overwritten
C. While booting, the machine may create temporary files that can delete evidence
D. Secure delete programs work by completely overwriting the file in one go
Answer: C
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NO.4 You are contracted to work as a computer forensics investigator for a regional bank that has four
30 TB storage area networks that store customer data. What method would be most efficient for
you to acquire digital evidence from this network?
A. create a compressed copy of the file with DoubleSpace
B. create a sparse data copy of a folder or file
C. make a bit-stream disk-to-image fileC
D. make a bit-stream disk-to-disk file
Answer: C
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NO.5 If you come across a sheepdip machine at your client site, what would you infer?
A. A sheepdip coordinates several honeypots
B. A sheepdip computer is another name for a honeypot
C. A sheepdip computer is used only for virus-checking.
D. A sheepdip computer defers a denial of service attack
Answer: C
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NO.6 With the standard Linux second extended file system (Ext2fs), a file is deleted when the inode
internal link count reaches ________.
A. 0
B. 10
C. 100
D. 1
Answer: A
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NO.7 The offset in a hexadecimal code is:
A. The last byte after the colon
B. The 0x at the beginning of the code
C. The 0x at the end of the code
D. The first byte after the colon
Answer: B
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NO.8 A suspect is accused of violating the acceptable use of computing resources, as he has visited
adult websites and downloaded images. The investigator wants to demonstrate that the suspect
did indeed visit these sites. However, the suspect has cleared the search history and emptied the
cookie cache. Moreover, he has removed any images he might have downloaded. What can the
investigator do to prove the violation? Choose the most feasible option.
A. Image the disk and try to recover deleted files
B. Seek the help of co-workers who are eye-witnesses
C. Check the Windows registry for connection data (You may or may not recover)
D. Approach the websites for evidence
Answer: A
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NO.9 What does the superblock in Linux define?
A. file system names
B. available space
C. location of the first inode
D. disk geometry
Answer: B, C, D
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NO.10 What type of attack occurs when an attacker can force a router to stop forwarding packets by
flooding the router with many open connections simultaneously so that all the hosts behind the
router are effectively disabled?
A. digital attack
B. denial of service
C. physical attack
D. ARP redirect
Answer: B
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NO.11 A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is
an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the
attacker by studying the log. Please note that you are required to infer only what is explicit in the
excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting,
basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.)
03/15-20:21:24.107053 211.185.125.124:3500 -> 172.16.1.108:111
TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF
***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32
TCP Options (3) => NOP NOP TS: 23678634 2878772
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111
UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84
Len: 64
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................
00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................
00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773
UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104
Len: 1084
47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8 G..c............
00 00 00 01 00 00 00 01 00 00 00 01 00 00 00 20 ...............
3A B1 5E E5 00 00 00 09 6C 6F 63 61 6C 68 6F 73 :.
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