2013年6月28日星期五

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Code d'Examen: 250-315

Nom d'Examen: Symantec (Administration of Symantec Endpoint Protection 12.1)

Questions et réponses: 167 Q&As

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NO.1 Which Symantec Endpoint Protection 12.1 component provides single-sign-on to the Symantec
Endpoint Protection Manager and other products, along with cross-product reporting?
A. Symantec Reporting server
B. Symantec Security Information Manager
C. IT Analytics
D. Symantec Protection Center
Answer: D

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NO.2 Which Symantec Endpoint Protection 12.1 component uses reputation to evaluate a file?
A. Shared Insight Cache server
B. Symantec Endpoint Protection client
C. Symantec Endpoint Protection Manager
D. LiveUpdate Administrator server
Answer: B

Symantec   250-315   250-315   250-315

NO.3 A company is experiencing a malware outbreak. The company deploys Symantec Endpoint Protection
12.1, with only Virus and Spyware Protection, Application and Device Control, and Intrusion Prevention
technologies. Why would Intrusion Prevention be unable to block all communications from an attacking
host?
A. Intrusion Prevention needs the firewall component to block all traffic from the attacking host.
B. Intrusion Prevention blocks the attack only if the administrator wrote a signature for it.
C. Intrusion Prevention definitions are out-of-date.
D. Intrusion Prevention is set to log only.
Answer: A

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NO.4 How many Symantec Endpoint Protection Managers can be connected to an embedded database?
A. 1
B. 2
C. 5
D. 10
Answer: A

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NO.5 Which component is required in order to run Symantec Endpoint Protection 12.1 protection
technologies?
A. Symantec Endpoint Protection Manager
B. Symantec Endpoint Protection client
C. LiveUpdate Administrator server
D. Symantec Protection Center
Answer: B

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NO.6 How can an administrator manage multiple, independent companies from one database while
maintaining independent groups, computers, and policies?
A. Set up limited administrators with appropriate rights.
B. Set up separate domains.
C. Set up additional sites using a single database.
D. Set up separate locations and turn off inheritance.
Answer: B

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NO.7 How does the Intrusion Prevention System add an additional layer of protection to Network Threat
Protection?
A. It inspects the TCP packet headers and tracks the sequence number.
B. It performs deep packet inspection, reading the packet headers, and data portion.
C. It examines TCP/IP traffic from the application and traces the source of the traffic.
D. It monitors IP datagrams for abnormalities.
Answer: B

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NO.8 A financial company has a security policy that prevents banking system workstations from connecting to
the internet. Which Symantec Endpoint Protection 12.1 protection technology will be prevented from
working on the company's workstations?
A. Insight
B. Application and Device Control
C. Network Threat Protection
D. LiveUpdate
Answer: A

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NO.9 Which Symantec Endpoint Protection 12.1 defense mechanism provides protection against worms like
W32.Silly.FDC, which propagate from system to system through the use of autorun.inf files?
A. Application Control
B. SONAR
C. Client Firewall
D. Exceptions
Answer: A

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NO.10 Which two objects in the Symantec Endpoint Protection Manager console describe the most granular
level to which a policy can be applied? (Select two.)
A. Site
B. Domain
C. Group
D. Location
E. Computer
F. User
Answer: C,D

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NO.11 Which Symantec Endpoint Protection 12.1 component uses Sybase SQL Anywhere?
A. Symantec Endpoint Protection Manager embedded database
B. Symantec Endpoint Protection Manager remote database
C. LiveUpdate Administrator server
D. Shared Insight Cache server
Answer: A

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NO.12 According to Symantec, what is a botnet.?
A. systems infected with the same virus strain
B. groups of systems performing remote tasks without the users' knowledge
C. groups of computers configured to steal credit card records
D. compromised systems opening communication to an IRC channel
Answer: B

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NO.13 A company with one site has a factory with computers in the manufacturing area. Both factory
managers and operators need to log in to these shared computers. Different policies will be applied
depending on whether the individual logging in to the machine is a manager or an operator. Which
Symantec Endpoint Protection 12.1 feature provides this ability?
A. Computer mode
B. Active Directory synchronization
C. User mode
D. Console authentication
Answer: C

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NO.14 An administrator is logged in to the Symantec Endpoint Protection Manager (SEPM) console for a
system named SEPM01. The groups and policies that were previously in the SEPM01 console are
unavailable and have been replaced with unfamiliar groups and policies. What was a possible reason for
this change?
A. The administrator was modified from using Computer mode to User mode.
B. The administrator was logged in to the incorrect domain for SEPM01.
C. The administrator was changed from a limited administrator to a system administrator.
D. The administrator was using the Web console instead of the Java console.
Answer: B

Symantec examen   250-315   250-315   250-315   250-315

NO.15 Which Symantec Endpoint Protection 12.1 component provides services to improve the performance
of virtual client scanning?
A. Shared Insight Cache server
B. LiveUpdate Administrator server
C. Symantec Protection Center
D. Group Update Provider
Answer: A

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NO.16 Which Symantec Endpoint Protection 12.1 protection technology provides the primary protection layers
against zero-day network attacks?
A. SONAR
B. Client Firewall
C. Intrusion Prevention
D. System Lockdown
Answer: C

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NO.17 Drive-by downloads are a common vector of infections. Some of these attacks use encryption to bypass
traditional defense mechanisms. Which Symantec Endpoint Protection 12.1 protection technology blocks
such obfuscated attacks?
A. SONAR
B. Bloodhound heuristic virus detection
C. Client Firewall
D. Browser Intrusion Prevention
Answer: D

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NO.18 The fake antivirus family "PC scout" infects systems with a similar method regardless of its variant.
Which SONAR sub-feature can block new variants of the same family, based on sequence of events?
A. artificial intelligence
B. behavioral heuristic
C. human authored signatures
D. behavioral policy lockdown
Answer: C

Symantec   250-315   250-315 examen   250-315 examen

NO.19 In addition to performance improvements, which two benefits does Insight provide? (Select two.)
A. reputation scoring for documents
B. zero-day threat detection
C. protection against system file modifications
D. false positive mitigation
E. blocking of malicious websites
Answer: B,D

Symantec   250-315 examen   250-315

NO.20 Which Symantec Endpoint Protection 12.1 component improves performance because known good
files are skipped?
A. LiveUpdate Administrator server
B. Group Update Provider
C. Shared Insight Cache server
D. Central Quarantine server
Answer: C

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Code d'Examen: ST0-141

Nom d'Examen: Symantec (Symantec Backup Exec 2012 Technical Assessment)

Questions et réponses: 150 Q&As

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NO.1 An administrator needs to restore a mailbox to an Exchange 2010 Database Availability Group. Which
server must have an installed Agent for Windows in order to restore from a GRT enabled backup of
Exchange?
A. the Edge Transport server
B. the Active Mailbox server
C. the Client Access server
D. the Passive Mailbox server
Answer: C

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NO.2 An administrator needs to use the Agent for VMware and Hyper-V to protect a VMware virtual machine
hosting Microsoft Exchange. The administrator needs to restore granular application objects, such as
emails, from the backup sets that are captured from the virtual machine hosting Exchange. Which action
should the administrator take before configuring a backup definition for the virtual machine hosting
Exchange?
A. run the Exchange optimizer utility
B. manually install VMware tools on the virtual machine
C. install the Agent for Windows on the virtual machine hosting Exchange
D. manually truncate Exchange transaction logs
Answer: C

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NO.3 An administrator needs to restore multiple emails from a GRT enabled backup of Exchange to a file.
Which file format will be created?
A. .MSG
B. .CAB
C. .PST
D. .OST
Answer: C

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NO.4 Which tool should be used to collect debug logs for a failing backup of a remote server.?
A. BEUtility.exe
B. Ramcmd.exe
C. VxMon.exe
D. SGMon.exe
Answer: D

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NO.5 An administrator plans to use Symantec Backup Exec 2012 data deduplication capabilities to protect a
Hyper-V environment. The administrator needs to leverage client-side deduplication and image-based
backups of the Hyper-V virtual machines. How does Symantec Backup Exec 2012 accomplish this task?
A. The Agent for Windows installed on the Hyper-V host performs client-side deduplication.
B. Backup data is deduplicated "in flight" during transport to the Symantec Backup Exec server.
C. Hyper-V virtual machines use the .VHD format for virtual disks, which is deduplicated by definition.
D. The PureDisk client installed to the Hyper-V secondary server performs client-side deduplication.
Answer: A

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NO.6 Which Symantec Backup Exec 2012 troubleshooting tool should an end user use before contacting
Symantec for additional support?
A. VxGather
B. Collect Debug Output
C. Symantec Backup Exec Support Tool
D. BEDiag
Answer: C

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NO.7 Which two behaviors of the Symantec Backup Exec 2012 Agent for Applications and Databases apply
to Microsoft Active Directory? (Select two.)
A. It is installed as a separate add-on component.
B. Windows Active Directory database can be backed up while online.
C. It is a system service that runs on remote Windows servers where active directory is installed.
D. Granular restore of individual Active Directory objects and attributes is unsupported.
E. It requires Agent for Windows to be running on the domain controller.
Answer: B,E

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NO.8 For GRT operations, in which two instances must the default path for the TEMP directory specified in
"Symantec Backup Exec 2012 > Configuration and settings > Backup Exec Settings > Granular Recovery
Technology" be modified? (Select two.)
A. when the default path is the system volume
B. when the default path is a mapped drive letter
C. when the default path is NTFS
D. when the default path is FAT32
E. when the default path contains the Windows page file
Answer: A,D

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NO.9 Which Symantec Backup Exec 2012 default global scheduling option allows jobs to be cancelled
without manual intervention?
A. job auto cancel after 'x' hours after its scheduled start time
B. kill the job if it is still running 'x' hours after its scheduled start time
C. terminate the job if it is still running 'x' hours if no data has incremented
D. cancel the job if it is still running 'x' hours after its scheduled start time
Answer: D

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NO.10 In Symantec Backup Exec 2012, scheduled convert to virtual jobs can be configured to support which
two sources? (Select two.)
A. all differential backups
B. all full backups
C. most recent snap
D. last incremental with changed block tracking enabled
E. most recent full backup
Answer: B,E

Symantec   ST0-141   ST0-141 examen

NO.11 A user requests the restore of files from the backup of a different server. The administrator performs a
redirected restore to the user's folder. Which "Restore site list and item level permissions" option must the
administrator select so the user can use the restored files?
A. restore only the NTFS permissions
B. restore files with the NTFS permissions of the destination folder
C. restore files without their NTFS permissions
D. restore files with their NTFS partitions
Answer: C

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NO.12 A backup job failed with an access denied error message. Which option in the backup job property can
be used to set the correct permissions?
A. verify credentials
B. user account credentials
C. validate credentials
D. test/edit credentials
Answer: D

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NO.13 A job runs with a custom error-handling rule in addition to the default error-handing rule. What will
happen?
A. The custom error-handling rule will apply.
B. The default error-handling rule will apply.
C. The job will fail.
D. The administrator will be prompted to select the rule.
Answer: A

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NO.14 Which two options are supported by the Checkpoint Restart feature of Symantec Backup Exec 2012?
(Select two.)
A. FAT32 volumes
B. NTFS volumes
C. Linux computers
D. Cluster Shared Volumes (CSV)
E. VSS
Answer: B,E

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NO.15 Where are the Symantec Backup Exec Job Log files stored by default?
A. \Program Files\Symantec\Backup Exec
B. \Program Files\Symantec\Backup Exec\Data
C. \Program Files\Symantec\Backup Exec\Logs
D. \Program Files\Symantec\Backup Exec\Log
Answer: B

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NO.1 }

NO.2 System.out.println("run.");

NO.3 }

NO.4 }
Which statement is true?
A. This code can throw an InterruptedException.
B. This code can throw an IllegalMonitorStateException.
C. This code can throw a TimeoutException after ten minutes.
D. Reversing the order of obj.wait() and obj.notify() might cause this method to complete normally.
E. A call to notify() or notifyAll() from another thread might cause this method to complete normally.
F. This code does NOT compile unless "obj.wait()" is replaced with "((Thread) obj).wait()".
Answer: B

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4. Click the Exhibit button.What is the output if the main() method is run?
Given:
10. public class Starter extends Thread {
11. private int x = 2;
12. public static void main(String[] args) throws Exception {
13. new Starter().makeItSo();

NO.5 Thread t = new Thread(new Threads2());

NO.6 public Starter() {

NO.7 Given:
1. public class Threads2 implements Runnable {

NO.8 System.out.println("End of method.");

NO.9 x = 5;

NO.10 }
Which two can be results? (Choose two.)
A. java.lang.RuntimeException: Problem
B. run. java.lang.RuntimeException: Problem
C. End of method. java.lang.RuntimeException: Problem
D. End of method. run. java.lang.RuntimeException: Problem
E. run. java.lang.RuntimeException: ProblemEnd of method.
Answer: DE

SUN   certification 310-065   310-065
2. Which two statements are true? (Choose two.)
A. It is possible for more than two threads to deadlock at once.
B. The JVM implementation guarantees that multiple threads cannot enter into a deadlocked state.
C. Deadlocked threads release once their sleep() method's sleep duration has expired.
D. Deadlocking can occur only when the wait(), notify(), and notifyAll() methods are used incorrectly.
E. It is possible for a single-threaded application to deadlock if synchronized blocks are used incorrectly.
F. If a piece of code is capable of deadlocking, you cannot eliminate the possibility of deadlocking by
insertinginvocations of Thread.yield().
Answer:AF

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3. Given:
7.void waitForSignal() {
8.Object obj = new Object();
9.synchronized (Thread.currentThread()) {
10.obj.wait();
11.obj.notify();
12.}

NO.11 start();

NO.12 }

NO.13 }

NO.14 }
What is the result?
A. 4321
B. 0000
C. An exception is thrown at runtime.
D. Compilation fails because of an error in line 18.
Answer: D

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12. Given:
11. public class Rainbow {
12. public enum MyColor {
13 RED(0xff0000), GREEN(0x00ff00), BLUE(0x0000ff);
14. private final int rgb;
15. MyColor(int rgb) { this.rgb = rgb; }
16. public int getRGB() { return rgb; }
17. };
18. public static void main(String[] args) {
19. // insert code here
20. }
21. }
Which code fragment, inserted at line 19, allows the Rainbow class to compile?
A. MyColor skyColor = BLUE;
B. MyColor treeColor = MyColor.GREEN;
C. if(RED.getRGB() < BLUE.getRGB()) { }
D. Compilation fails due to other error(s) in the code.
E. MyColor purple = new MyColor(0xff00ff);
F. MyColor purple = MyColor.BLUE + MyColor.RED;
Answer: B

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13. Given:
11. class Mud {
12. // insert code here
13. System.out.println("hi");
14 }
15. }
And the following five fragments:
public static void main(String...a) {
public static void main(String.* a) {
public static void main(String... a) {
public static void main(String[]... a) {
public static void main(String...[] a) {
How many of the code fragments, inserted independently at line 12, compile?
A. 0
B. 1
C. 2
D. 3
E. 4
F. 5
Answer: D

SUN   310-065   310-065 examen
14. Given:
5. class Atom {
6. Atom() { System.out.print("atom "); }
7. }
8. class Rock extends Atom {
9. Rock(String type) { System.out.print(type); }
10. }
11. public class Mountain extends Rock {
12. Mountain() {
13. super("granite ");
14. new Rock("granite ");
15. }
16. public static void main(String[] a) { new Mountain(); }
17. }
What is the result?
A. Compilation fails.
B. atom granite
C. granite granite
D. atom granite granite
E. An exception is thrown at runtime.
F. atom granite atom granite
Answer: F

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15. Given:
1. interface TestA { String toString(); }
2. public class Test {
3. public static void main(String[] args) {
4. System.out.println(new TestA() {
5. public String toString() { return "test"; }
6. });
7. }
8. }
What is the result?
A. test
B. null
C. An exception is thrown at runtime.
D. Compilation fails because of an error in line 1.
E. Compilation fails because of an error in line 4.
F. Compilation fails because of an error in line 5.
Answer:A

SUN   310-065   310-065   310-065 examen   certification 310-065
16. Given:
11. public static void parse(String str) {
12. try {
13. float f = Float.parseFloat(str);
14. } catch (NumberFormatException nfe) {
15. f = 0;
16. } finally {
17 System.out.println(f);
18. }
19. }
20. public static void main(String[] args) {
21. parse("invalid");
22. }
What is the result?
A. 0.0
B. Compilation fails.
C. A ParseException is thrown by the parse method at runtime.
D. A NumberFormatException is thrown by the parse method at runtime.
Answer: B

SUN examen   certification 310-065   310-065 examen
17. Given:
1. public class Blip {
2. protected int blipvert(int x) { return 0; }
3. }
4. class Vert extends Blip {
5. // insert code here
6. }
Which five methods, inserted independently at line 5, will compile? (Choose five.)
A. public int blipvert(int x) { return 0; }
B. private int blipvert(int x) { return 0; }
C. private int blipvert(long x) { return 0; }
D. protected long blipvert(int x) { return 0; }
E. protected int blipvert(long x) { return 0; }
F. protected long blipvert(long x) { return 0; }
G. protected long blipvert(int x, int y) { return 0; }
Answer: ACEFG

SUN examen   310-065   310-065
18. Given:
1. class Super {
2. private int a;
3. protected Super(int a) { this.a = a; }
4. } ...
11. class Sub extends Super {
12. public Sub(int a) { super(a); }
13. public Sub() { this.a = 5; }
14. }
Which two, independently, will allow Sub to compile? (Choose two.)
A. Change line 2 to:public int a;
B. Change line 2 to: protected int a;
C. Change line13 to:public Sub() { this(5); }
D. Change line 13 to:public Sub() { super(5); }
E. Change line13 to:public Sub() { super(a); }
Answer: CD

SUN examen   certification 310-065   310-065 examen   310-065   310-065
19. Which Man class properly represents the relationship "Man has a best friend who is a Dog"?
A. class Man extends Dog { }
B. class Man implements Dog { }
C. class Man { private BestFriend dog; }
D. class Man { private Dog bestFriend; }
E. class Man { private Dog<bestFriend>; }
F. class Man { private BestFriend<dog>; }
Answer: D

SUN   310-065   310-065   310-065
20. Given:
1. package test;
2.
3. class Target {
4. public String name = "hello";
5. }
What can directly access and change the value of the variable name?
A. any class
B. only the Target class
C. any class in the test package
D. any class that extends Target
Answer: C

SUN examen   310-065   310-065 examen   310-065

NO.15 public static void main(String[] args) {

NO.16 x = x - 1;

NO.17 t.start();

NO.18 public void makeItSo() throws Exception {

NO.19 throw new RuntimeException("Problem");

NO.20 join();

NO.21 System.out.println(x);

NO.22 }

NO.23 public void run() { x *= 2; }

NO.24 }
A. 4
B. 5
C. 8
D. 9
E. Compilation fails.
F. An exception is thrown at runtime.
G. It is impossible to determine for certain.
Answer: D

SUN   310-065   310-065 examen   310-065 examen
5. Given:
11.class PingPong2 {
12.synchronized void hit(long n) {
13.for(int i = 1; i < 3; i++)
14.System.out.print(n + "-" + i + " ");
15.}
16.}
17.public class Tester implements Runnable {
18.static PingPong2 pp2 = new PingPong2();
19.public static void main(String[] args) {
20.new Thread(new Tester()).start();
21.new Thread(new Tester()).start();
22.}
23.public void run() { pp2.hit(Thread.currentThread().getId()); }
24.}
Which statement is true?
A. The output could be 5-1 6-1 6-2 5-2
B. The output could be 6-1 6-2 5-1 5-2
C. The output could be 6-1 5-2 6-2 5-1
D. The output could be 6-1 6-2 5-1 7-1
Answer: B

SUN examen   310-065 examen   310-065 examen
6. Given:
1. public class Threads4 {
2. public static void main (String[] args) {
3. new Threads4().go();
4. }
5. public void go() {
6. Runnable r = new Runnable() {
7. public void run() {
8. System.out.print("foo");
9. }
10. };
11. Thread t = new Thread(r);
12. t.start();
13. t.start();
14. }
15. }
What is the result?
A. Compilation fails.
B. An exception is thrown at runtime.
C. The code executes normally and prints "foo".
D. The code executes normally, but nothing is printed.
Answer: B

SUN   310-065   310-065
7. Given:
11. public abstract class Shape {
12. private int x;
13. private int y;
14. public abstract void draw();
15. public void setAnchor(int x, int y) {
16. this.x = x;
17. this.y = y;
18. }
19. }
Which two classes use the Shape class correctly? (Choose two.)
A. public class Circle implements Shape {private int radius; }
B. public abstract class Circle extends Shape { private int radius; }
C. public class Circle extends Shape { private int radius; public void draw(); }
D. public abstract class Circle implements Shape { private int radius; public void draw(); }
E. public class Circle extends Shape { private int radius; public void draw() {/* code here */}
F. public abstract class Circle implements Shape { private int radius; public void draw() { /* code here */ }
Answer: BE

SUN   310-065 examen   310-065 examen   310-065   310-065
8. Given:
11. public class Barn {
12. public static void main(String[] args) {
13. new Barn().go("hi", 1);
14. new Barn().go("hi", "world", 2);
15. }
16. public void go(String... y, int x) {
17. System.out.print(y[y.length - 1] + " ");
18. }
19. }
What is the result?
A. hi hi
B. hi world
C. world world
D. Compilation fails.
E. An exception is thrown at runtime.
Answer: D

certification SUN   certification 310-065   310-065   certification 310-065   310-065 examen
9.Given:
10.class Nav{
11. public enum Direction { NORTH, SOUTH, EAST, WEST }
12. }
13. public class Sprite{
14. // insert code here
15. }
Which code, inserted at line 14, allows the Sprite class to compile?
A. Direction d = NORTH;
B. Nav.Direction d = NORTH;
C. Direction d = Direction.NORTH;
D. Nav.Direction d = Nav.Direction.NORTH;
Answer: D

certification SUN   310-065   310-065   310-065   certification 310-065
10. Click the Exhibit button.
1. public interface A {
2. public void doSomething(String thing);
3. }
1. public class AImpl implements A {
2. public void doSomething(String msg) { }
3. }
1. public class B {
2. public A doit() {
3. // more code here
4. }
5.
6. public String execute() {
7. // more code here
8. }
9. }
1. public class C extends B {
2. public AImpl doit() {
3. // more code here
4. }
5.
6. public Object execute() {
7. // more code here
8. }
9. }
Which statement is true about the classes and interfaces in the exhibit?
A. Compilation will succeed for all classes and interfaces.
B. Compilation of class C will fail because of an error in line 2.
C. Compilation of class C will fail because of an error in line 6.
D. Compilation of class AImpl will fail because of an error in line 2.
Answer: C

certification SUN   certification 310-065   certification 310-065   310-065   certification 310-065
11. Click the Exhibit button.
11. class Person {
12. String name = "No name";
13. public Person(String nm) { name = nm; }
14. }
15.
16. class Employee extends Person {
17. String empID = "0000";
18. public Employee(String id) { empID = id; }
19. }
20.
21. public class EmployeeTest {
22. public static void main(String[] args) {
23. Employee e = new Employee("4321");
24. System.out.println(e.empID);
25. }

NO.25 public void run() {

NO.26

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Code d'Examen: 090-055

Nom d'Examen: SCO (UNIXWARE 7 NETWORK ADMINISTRATION V10A1)

Questions et réponses: 72 Q&As

090-055 Démo gratuit à télécharger: http://www.pass4test.fr/090-055.html


NO.1 Which is the primary file used to configure the sendmail daemon?
A. /etc/mailcap
B. /etc/sendmail.cf
C. /etc/rc2.d/S81sendmail
D. /etc/mail/sendmailrc
Answer: B

SCO   090-055 examen   090-055 examen

NO.2 Which statement concerning UnixWare 7 anonymous FTP is FALSE?
A. Anonymous FTP can be configured with the SCOadmin FTP Server Manager.
B. Anonymous FTP grants limited file transfer access to unauthenticated users.
C. You can limit how many simultaneous anonymous FTP users are allowed.
D. The address of the anonymous FTP client system is NOT recorded on the server.
Answer: D

certification SCO   090-055 examen   090-055   090-055

NO.3 What does the Internet Protocol level of the TCP/IP protocol stack use to verify that incoming
data
is for this host?
A. The Ethernet address
B. The IP address
C. Cyclic Redundancy Check (CRC) error checking
D. The port number
Answer: B

SCO   090-055 examen   certification 090-055   090-055

NO.4 What is the effect of the following route command:
route add 200.100.10.20 200.100.30.40
A. It adds routes to the two hosts 200.100.10.20 and 200.100.30.40.
B. It adds a route to the host 200.100.10.20 through the router 200.100.30.40.
C. It adds a route to the host 200.100.30.40 through the router 200.100.10.20.
D. It is a syntax error.
Answer: B

SCO examen   certification 090-055   090-055 examen   090-055

NO.5 Which proxy server is installed by default with UnixWare 7?
A. Netscape Proxy Server
B. Squid
C. CERN HTTPD
D. No proxy servers are installed by default with UnixWare 7.
Answer: D

SCO   090-055 examen   090-055 examen   certification 090-055

NO.6 Which mail user agent is NOT installed by default with UnixWare 7?
A. mailx
B. dtmail
C. pine
D. elm
Answer: D

SCO   090-055   090-055   certification 090-055   090-055

NO.7 If a zone has a primary and a secondary name server, when does the secondary name server
perform a zone transfer?
A. On a fixed schedule specified by the refresh parameter of the SOA record in the configuration
files of the primary name server
B. On a fixed schedule specified by the refresh parameter of the SOA record in the configuration
files of the secondary name server
C. Every time the secondary name server successfully contacts the primary name server
D. Only when the secondary server successfully contacts the primary name server and detects
that the primary name servers serial number has changed
Answer: D

SCO   090-055   090-055   certification 090-055   090-055

NO.8 In which level of the TCP/IP protocol stack does TCP Wrappers operate?
A. Application
B. Transport
C. Internet
D. Network Interface
Answer: A

SCO   090-055   090-055 examen   090-055

NO.9 Which program or protocol CANNOT be used to share UnixWare 7 files with a Windows client?
A. VisionFS
B. Advanced File and Print Server (AFPS)
C. Dynamic Host Configuration Protocol (DHCP)
D. Network File System (NFS)
Answer: C

SCO   090-055   090-055   090-055 examen   090-055 examen

NO.10 What does the following command do on a UnixWare 7 system:
nsfast enable 80
A. The Netscape FastTrack web browser is started, but will not restart at boot time.
B. The Netscape FastTrack web browser is started and will restart at boot time.
C. The Netscape FastTrack web server is started, but will not restart at boot time.
D. The Netscape FastTrack web server is started and will restart at boot time.
Answer: D

SCO examen   090-055   certification 090-055

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Code d'Examen: 090-601

Nom d'Examen: SCO (SCO OpenServer Release 6 Netwok Administration)

Questions et réponses: 73 Q&As

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Code d'Examen: A00-240

Nom d'Examen: SASInstitute (SAS Certified Statistical Business Analyst Using SAS 9: Regression and Modeling Credential)

Questions et réponses: 65 Q&As

A00-240 Démo gratuit à télécharger: http://www.pass4test.fr/A00-240.html


NO.1 This question will ask you to provide a missing option.
Complete the following syntax to test the homogeneity of variance assumption in the GLM
procedure:
Means Region / <insert option here> =levene;
A. test
B. adjust
C. var
D. hovtest
Answer: D

SASInstitute   A00-240 examen   A00-240

NO.2 A linear model has the following characteristics:
*A dependent variable (y)
*One continuous variable (xl), including a quadratic term (x12)
*One categorical (d with 3 levels) predictor variable and an interaction term (d by x1)
How many parameters, including the intercept, are associated with this model?
Enter your numeric answer in the space below. Do not add leading or trailing spaces to your
answer.
Answer: 7

NO.3 What is the default method in the LOGISTIC procedure to handle observations with missing
data?
A. Missing values are imputed.
B. Parameters are estimated accounting for the missing values.
C. Parameter estimates are made on all available data.
D. Only cases with variables that are fully populated are used.
Answer: D

certification SASInstitute   certification A00-240   A00-240 examen   A00-240 examen

NO.4 The following LOGISTIC procedure output analyzes the relationship between a binary response
and an ordinal predictor variable, wrist_size Using reference cell coding, the analyst selects Large
(L) as the reference level.
What is the estimated logit for a person with large wrist size?
Click the calculator button to display a calculator if needed.
A. 0.0819
B. 0.5663
C. -3.7727
D. -1.0415
Answer: D

SASInstitute   certification A00-240   A00-240 examen

NO.5 In partitioning data for model assessment, which sampling methods are acceptable? (Choose
two.)
A. Simple random sampling without replacement
B. Simple random sampling with replacement
C. Stratified random sampling without replacement
D. Sequential random sampling with replacement
Answer: A,C

SASInstitute   A00-240   A00-240   A00-240

NO.6 A company has branch offices in eight regions. Customers within each region are classified as
either "High Value" or "Medium Value" and are coded using the variable name VALUE. In the last
year, the total amount of purchases per customer is used as the response variable.
Suppose there is a significant interaction between REGION and VALUE. What can you conclude?
A. More high value customers are found in some regions than others.
B. The difference between average purchases for medium and high value customers depends on
the region.
C. Regions with higher average purchases have more high value customers.
D. Regions with higher average purchases have more medium value customers.
Answer: B

SASInstitute   certification A00-240   A00-240 examen   A00-240 examen   A00-240

NO.7 Suppose training data are oversampled in the event group to make the number of events and
nonevents
roughly equal. A logistic regression is run and the probabilities are output to a data set
NEW and given the variable name PE. A decision rule considered is, "Classify data as an event if
probability is greater than 0.5." Also the data set NEW contains a variable TG that indicates
whether there is an event (1=Event, 0= No event).
The following SAS program was used.
What does this program calculate?
A. Depth
B. Sensitivity
C. Specificity
D. Positive predictive value
Answer: B

SASInstitute   A00-240 examen   A00-240   A00-240 examen   A00-240

NO.8 A non-contributing predictor variable (Pr > |t| =0.658) is added to an existing multiple linear
regression model.
What will be the result?
A. An increase in R-Square
B. A decrease in R-Square
C. A decrease in Mean Square Error
D. No change in R-Square
Answer: A

certification SASInstitute   A00-240   A00-240   A00-240   A00-240

NO.9 Refer to the exhibit:
The box plot was used to analyze daily sales data following three different ad campaigns.
The business analyst concludes that one of the assumptions of ANOVA was violated.
Which assumption has been violated and why?
A. Normality, because Prob > F < .0001.
B. Normality, because the interquartile ranges are different in different ad campaigns.
C. Constant variance, because Prob > F < .0001.
D. Constant variance, because the interquartile ranges are different in different ad campaigns.
Answer: D

SASInstitute   A00-240   certification A00-240   A00-240 examen   A00-240

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RedHat meilleur examen RH302, questions et réponses

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Code d'Examen: RH302

Nom d'Examen: RedHat (Red Hat Certified Engineer on Redhat Enterprise Linux 5 (Labs))

Questions et réponses: 330 Q&As

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NO.1 CORRECT TEXT
You are giving RHCT Exam and in your Exam paper there is a question written, make successfully ping to
192.168.0.254.
Answer and Explanation:
In Network problem thinks to check:
1. IP Configuration: use ifconfig command either IP is assigned to interface or not?
2. Default Gateway is set or not?
3. Hostname is set or not?
4. Routing problem is there?
5. Device Driver Module is loaded or not?
6. Device is activated or not?
Check In this way:
1. use ifconfig command and identify which IP is assigned or not.
2. cat /etc/sysconfig/network ¨¤ What, What is written here. Actually here are these parameters
NETWORKING=yes or no
GATEWAY=x.x.x.x
HOSTNAME=?
NISDOMAIN=?
-Correct the file
3. Use vi /etc/sysconfig/network-scirpts/ifcfg-eth0 and check the proper options
DEVICE=eth0
ONBOOT=yes
BOOTPROTO=static
IPADDR=x.x.x.x
NETMAKS=x.x.x.x
GATEWAY=x.x.x.x
4. Use service network restart or start command

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NO.2 CORRECT TEXT
Successfully resolv to server1.example.com where your DNS server is 172.24.254.254
Answer and Explanation:
1. vi /etc/resolv.conf
nameserver 172.24.254.254
2. host server1.example.com

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NO.3 Press P to verify the partitions lists and remember the partitions name.

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NO.4 /dev/hda? /mnt/neo ext3 defaults 1 2

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NO.5 CORRECT TEXT
The System you are using is for NFS (Network File Services). Some important data are shared from your
system. Make automatically start the nfs and portmap services at boot time.
Answer and Explanation:
We can control the services for current session and for next boot time also. For current Session,we use
service servicename start or restart or stop or status. For automatically on next reboot time:
1. chkconfig servicename on or off
eg: chkconfig nfs on
chkconfig portmap on
or
ntsysv
Select the nfs and portmap services.
2. Reboot the system and identify whether services are running or not.

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NO.6 mke2fs -j /dev/hda? ¨¤ To create ext3 filesystem.

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NO.7 CORRECT TEXT
There are two different networks 192.168.0.0/24 and 192.168.1.0/24. Where 192.168.0.254 and
192.168.1.254 IP Address are assigned on Server. Verify your network settings by pinging
192.168.1.0/24 Network's Host.
Answer and Explanation:
1. vi /etc/sysconfing/network
NETWORKING=yes
HOSTNAME=station?.example.com
GATEWAY=192.168.0.254
2. service network restart
Or
1. vi /etc/sysconfig/network-scripts/ifcfg-eth0
DEVICE=eth0
ONBOOT=yes
BOOTPROTO=static
IPADDR=X.X.X.X
NETMASK=X.X.X.X
GATEWAY=192.168.0.254
2. ifdown eth0
3. ifup eth0

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NO.8 CORRECT TEXT
Your System is configured in 192.168.0.0/24 Network and your nameserver is 192.168.0.254.
Make successfully resolve to server1.example.com.
Answer and Explanation:
Very Easy question, nameserver is specified in question,
1. vi /etc/resolv.conf
nameserver 192.168.0.254
2. host server1.example.com

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NO.9 Or

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NO.10 mkdir /mnt/neo

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NO.11 CORRECT TEXT
Dig Server1.example.com, Resolve to successfully through DNS Where DNS server is
172.24.254.254
Answer and Explanation:
#vi /etc/resolv.conf
nameserver 172.24.254.254
# dig server1.example.com
#host server1.example.com
DNS is the Domain Name System, which maintains a database that can help your computer
translate domain names such as www.redhat.com to IP addresses such as 216.148.218.197. As
no individual DNS server is large enough to keep a database for the entire Internet, they can refer
requests to other DNS servers.
DNS is based on the named daemon, which is built on the BIND (Berkeley Internet Name Domain)
package developed through the Internet Software Consortium
Users wants to access by name so DNS will interpret the name into ip address. You need to specify the
Address if DNS server in each and every client machine. In Redhat Enterprise Linux, you need to specify
the DNS server into /etc/resolv.conf file.
After Specifying the DNS server address, you can verify using host, dig and nslookup commands.

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NO.12 CORRECT TEXT
One Package named zsh is dump on ftp://server1.example.com under /pub/updates directory and your
FTP server is 192.168.0.254. Install the package zsh.
Answer and Explanation:
1. rpm -ivh ftp://server1/example.com/pub/updates/zsh-*
or
1. Login to ftp server : ftp ftp://server1.example.com using anonymous user.
2. Change the directory: cd pub and cd updates
3. Download the package: mget zsh-*
4. Quit from the ftp prompt : bye
5. Install the package
6. rpm -ivh zsh-*
7. Verify either package is installed or not : rpm -q zsh

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NO.13 Verify by mounting on current Sessions also:

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NO.14 Type the Size: +100M ¨¤ You can Specify either Last cylinder of Size here.

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NO.15 CORRECT TEXT
Add a new logical partition having size 100MB and create the /data which will be the mount point for the
new partition.
Answer and Explanation:Use fdisk /dev/hda ¨¤ To create new parition.Type n ¨¤ For New
partitionsIt will ask for Logical or Primary Partitions. Press l for logical.It will ask for the Starting Cylinder:
Use the Default by pressing Enter Key.Type the Size: +100M ¨¤ You can Specify either Last cylinder of
Size here.Press P to verify the partitions lists and remember the partitions name.Press w to write on
partitions table.Either Reboot or use partprobe command.Use mkfs -t
ext3 /dev/hda?Ormke2fs -j /dev/hda? ¨¤ To create ext3 filesystem.vi /etc/fstabWrite:/dev/hda? /data
ext3 defaults 0 0Verify by mounting on current Sessions also:mount /dev/hda? /data

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NO.16 CORRECT TEXT
Your system is giving error while booting on Runlevel 5 . Make successfully boot your system in
runlevel 5.
Answer and Explanation:
While you load the X Window System, you will get the problem. To troubleshoot follow the
following steps:
1. Check the /tmp is full ?
2. Check your quota, hard limit is already crossed ?
3. Check xfs service is running ?
4. Boot the system on runlevel 3 and execute the system-config-display command
5. Edit the /etc/inittab to set default runlevel 5.
id:5:initdefault:

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NO.17 CORRECT TEXT
Change the root Password to redtophat
Answer and Explanation:Boot the system in Single user modeUse the passwd command

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NO.18 CORRECT TEXT
There is a server having 172.24.254.254 and 172.25.254.254. Your System lies on 172.24.0.0/16.
Make successfully ping to 172.25.254.254 by Assigning following IP: 172.24.0.x Where x is your station
number.
Answer and Explanation:
1. vi /etc/sysconfig/network-scripts/ifcfg-eth0
DEVICE=eth0
BOOTPROTO=static
ONBOOT=yes
IPADDR=x.x.x.x
NETMASK=x.x.x.x
2. Enter the IP Address as given station number by your examiner: example: 172.24.0.1
3. Enter Subnet Mask
4. Enter Default Gateway and primary name server
5. press on ok
6. ifdown eth0
7. ifup eth0
8. verify using ifconfig
In the lab server is playing the role of router, IP forwarding is enabled. Just set the Correct IP and gateway,
you can ping to 172.25.254.254.

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NO.19 CORRECT TEXT
Set the Hostname station?.example.com where ? is your Host IP Address.
Answer and Explanation:
1. hostname station?.example.com ¨¤ This will set the host name only for current session. To set
hostname permanently.
2. vi /etc/sysconfig/network
HOSTNAME=station?.example.com
3. service network restart

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NO.20 Use mkfs -t ext3 /dev/hda? Where ? is your partition number

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NO.21 CORRECT TEXT
Make Successfully Resolve to server1.example.com where DNS Server is 192.168.0.254.
Answer and Explanation: 1. vi /etc/resolv.conf
Write : nameserver 192.168.0.254

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NO.22 Write:

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NO.23 CORRECT TEXT
One Logical Volume is created named as myvol under vo volume group and is mounted. The Initial Size
of that Logical Volume is 400MB. Make successfully that the size of Logical Volume 200MB without losing
any data. The size of logical volume 200MB to 210MB will be acceptable.
Answer and Explanation:
1. First check the size of Logical Volume: lvdisplay /dev/vo/myvol
2. Make sure that the filesystem is in a consistent state before reducing:
# fsck -f /dev/vo/myvol
3. Now reduce the filesystem by 200MB.
# resize2fs /dev/vo/myvol 200M
4. It is now possible to reduce the logical volume.
#lvreduce /dev/vo/myvol -L 200M
4. Verify the Size of Logical Volume: lvdisplay /dev/vo/myvol
5. Verify that the size comes in online or not: df -h

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NO.24 Either Reboot or use partprobe command.

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NO.25 mount /dev/hda? /mnt/neo
4 CORRECT TEXT
Your System is going use as a router for 172.24.0.0/16 and 172.25.0.0/16. Enable the IP
Forwarding.
Answer and Explanation:
1. echo "1" >/proc/sys/net/ipv4/ip_forward
2. vi /etc/sysctl.conf
net.ipv4.ip_forward=1
/proc is the virtual filesystem, containing the information about the running kernel. To change the
parameter of running kernel you should modify on /proc. From Next reboot the system, kernel will
take the value from /etc/sysctl.conf.
5.CORRECT TEXT
Some users home directory is shared from your system. Using showmount -e localhost command, the
shared directory is not shown. Make access the shared users home directory.
Answer and Explanation:
1. Verify the File whether Shared or not ? : cat /etc/exports
2. Start the nfs service: service nfs start
3. Start the portmap service: service portmap start
4. Make automatically start the nfs service on next reboot: chkconfig nfs on
5. Make automatically start the portmap service on next reboot: chkconfig portmap on
6. Verify either sharing or not: showmount -e localhost
7. Check that default firewall is running on system ? if running flush the iptables using iptables -F and stop
the iptables service.
6.CORRECT TEXT
neo user tried by:
dd if=/dev/zero of=/home/neo/somefile bs=1024 count=70
files created successfully. Again neo tried to create file having 70K using following command:
dd if=/dev/zero of=/home/neo/somefile bs=1024 count=70
But he is unable to create the file. Make the user can create the file less then 70K.
Answer and Explanation:
Very Tricky question from redhat. Actually question is giving scenario to you to implement quota toneo
user. You should apply the quota to neo user on /home that neo user shouldn't occupied space more than
70K.
1. vi /etc/fstab
LABEL=/home /home ext3 defaults,usrquota 0 0 ¨¤ To enable th
quota on filesystem you should mount
the filesystem with usrquota for user quota and grpquota for group quota.
2. touch /home/aquota.user ¨¤Creating blank quota database file.
3. mount -o remount /home ¨¤ Remounting the /home with updated mount options. ou can verify that
/home is mounted with usrquota options or not using mount command.
4. quotacheck -u /home ¨¤ Initialization the quota on /home
5. edquota -u neo /home ¨¤ Quota Policy editor
See the snapshot
Disk quotas for user neo (uid 500):
Filesystem blocks soft hard inodes soft hard
/dev/mapper/vo-myvol 2 30 70 1 0 0
Can you set the hard limit 70 and soft limit as you think like 30.
Verify using the repquota /home command.
7.CORRECT TEXT
One Logical Volume is created named as myvol under vo volume group and is mounted. The Initial Size
of that Logical Volume is 124MB. Make successfully that the size of Logical Volume 245MB without losing
any data. The size of logical volume 240MB to 255MB will be acceptable.
Answer and Explanation:
1. First check the size of Logical Volume: lvdisplay /dev/vo/myvol
2. Increase the Size of Logical Volume: lvextend -L+121M /dev/vo/myvol
3. Make Available the size on online: resize2fs /dev/vo/myvol
4. Verify the Size of Logical Volume: lvdisplay /dev/vo/myvol
5. Verify that the size comes in online or not: df -h
We can extend the size of logical Volume using the lvextend command. As well as to decrease the
size of Logical Volume, use the lvresize command. In LVM v2 we can extend the size of Logical
Volume without unmount as well as we can bring the actual size of Logical Volume on online using
ext2online command.
8.CORRECT TEXT
Quota is implemented on /data but not working properly. Find out the
Problem and implement the quota to user1 to have a soft limit 60 inodes
(files) and hard limit of 70 inodes (files).
Answer and Explanation:
Quotas are used to limit a user's or a group of users' ability to consume disk space. This prevents a small
group of users from monopolizing disk capacity and potentially interfering with other users or the entire
system. Disk quotas are commonly used by ISPs, by Web hosting companies, on FTP sites, and on
corporate file servers to ensure continued availability of their systems.
Without quotas, one or more users can upload files on an FTP server to the point of filling a filesystem.
Once the affected partition is full, other users are effectively denied upload access to the disk. This is also
a reason to mount different filesystem directories on different partitions. For example, if you only had
partitions for your root (/) directory and swap space, someone uploading to your computer could fill up all
of the space in your root directory (/). Without at least a little free space in the root directory (/), your
system could become unstable or even crash.
You have two ways to set quotas for users. You can limit users by inodes or by kilobyte-sized disk blocks.
Every Linux file requires an inode. Therefore, you can limit users by the number of files or by absolute
space. You can set up different quotas for different filesystems. For example, you can set different quotas
for users on the /home and /tmp directories if they are mounted on their own partitions.
Limits on disk blocks restrict the amount of disk space available to a user on your system. Older versions
of Red Hat Linux included LinuxConf, which included a graphical tool to configure quotas.
As of this writing, Red Hat no longer has a graphical quota configuration tool. Today, you can configure
quotas on RHEL only through the command line interface.
1. vi /etc/fstab
/dev/hda11 /data ext3 defaults,usrquota 1 2
2. Either Reboot the System or remount the partition.
Mount -o remount /dev/hda11 /data
3. touch /data/aquota.user
4. quotacheck -ufm /data
5. quotaon -u /data
6. edquota -u user1 /data
and Specified the Soft limit and hard limit on opened file.
To verify either quota is working or not:
Soft limit specify the limit to generate warnings to users and hard limit can't cross by the user. Use the
quota command or repquota command to monitor the quota information.
9.CORRECT TEXT
One Logical Volume named lv1 is created under vg0. The Initial Size of that Logical Volume is 100MB.
Now you required the size 500MB. Make successfully the size of that Logical Volume 500M without losing
any data. As well as size should be increased online.
Answer and Explanation:
The LVM system organizes hard disks into Logical Volume (LV) groups. Essentially, physical hard disk
partitions (or possibly RAID arrays) are set up in a bunch of equal-sized chunks known as Physical
Extents (PE). As there are several other concepts associated with the LVM system, let's start with some
basic definitions:
* Physical Volume (PV) is the standard partition that you add to the LVM mix. Normally, a physical volume
is a standard primary or logical partition. It can also be a RAID array.
* Physical Extent (PE) is a chunk of disk space. Every PV is divided into a number of equal sized
PEs. Every PE in a LV group is the same size. Different LV groups can have different sized PEs.
* Logical Extent (LE) is also a chunk of disk space. Every LE is mapped to a specific PE.
* Logical Volume (LV) is composed of a group of LEs. You can mount a filesystem such as /home
and /var on an LV.
* Volume Group (VG) is composed of a group of LVs. It is the organizational group for LVM. Most
of the commands that you'll use apply to a specific VG.
1. Verify the size of Logical Volume: lvdisplay /dev/vg0/lv1
2. Verify the Size on mounted directory: df -h or df -h mounted directory name
3. Use : lvextend -L+400M /dev/vg0/lv1
4. resize2fs /dev/vg0/lv1 ¨¤ to bring extended size online.
5. Again Verify using lvdisplay and df -h command.
10.CORRECT TEXT
Create one partitions having size 100MB and mount it on /data.
Answer and Explanation:
1. Use fdisk /dev/hda ¨¤ To create new partition.
2. Type n ¨¤ For New partitions
3. It will ask for Logical or Primary Partitions. Press l for logical.
4. It will ask for the Starting Cylinder: Use the Default by pressing Enter Key.
5. Type the Size: +100M ¨¤ You can Specify either Last cylinder of Size here.
6. Press P to verify the partitions lists and remember the partitions name.
7. Press w to write on partitions table.
8. Either Reboot or use partprobe command.
9. Use mkfs -t ext3 /dev/hda?
Or
mke2fs -j /dev/hda? ¨¤ To create ext3 filesystem
10. vi /etc/fstab
Write:
/dev/hda? /data ext3 defaults 1 2
11. Verify by mounting on current Sessions also:
mount /dev/hda? /data
11 CORRECT TEXT
You are new System Administrator and from now you are going to handle the system and your
main task is Network monitoring, Backup and Restore. But you don't know the root password.
Change the root password to redhat and login in default Runlevel.
Answer and Explanation:
When you Boot the System, it starts on default Runlevel specified in /etc/inittab:
Id:?:initdefault:
When System Successfully boot, it will ask for username and password. But you don't know the
root's password. To change the root password you need to boot the system into single user mode.
You can pass the kernel arguments from the boot loader.
1. Restart the System.
2. You will get the boot loader GRUB screen.
3. Press a and type 1 or s for single mode
ro root=LABEL=/ rhgb queit s
4. System will boot on Single User mode.
5. Use passwd command to change.
6. Press ctrl+d
12 CORRECT TEXT
There are more then 400 Computers in your Office. You are appointed as a System Administrator.
But you don't have Router. So, you are going to use your One Linux Server as a Router. How will you
enable IP packets forward?
Answer and Explanation:
1. /proc is the virtual filesystem, we use /proc to modify the kernel parameters at running time.
# echo "1" >/proc/sys/net/ipv4/ip_forward
2. /etc/sysctl.conf ¨¤ when System Reboot on next time, etc/rc.d/rc.sysinit scripts reads the file
/etc/sysctl.conf. To enable the IP forwarding on next reboot also you need to set the parameter.
net.ipv4.ip_forward=1
Here 0 means disable, 1 means enable.
13.CORRECT TEXT
You Completely Install the Redhat Enterprise Linux 5 on your System. While start the system, it's
giving error to load X window System. How will you fix that problem and make boot successfully
run X Window System.
Answer and Explanation:
Think while Problems occurred on booting System on Runlevel 5 (X Window)./tmp is full ornotQuota is
already reachedVideo card or resolution or monitor is misconfigured.xfs service is running or not.
Do These:
1. df -h /tmp ¨¤ /tmp is full remove the unnecessary filequota username ¨¤ if quota is alread
reached remove unnecessary file from home directory.Boot the System in runlevel 3.¨¤ you can
pass the Kernel Argument from boot loader.Use command: system-config-display ¨¤ It will display a
dialog to configure the monitor, Video card, resolution etc.Set the Default Runlevel 5 in /etc/inittab
id:5:initdefault:
6. Reboot the System you will get the GUI login Screen.
14 CORRECT TEXT
There are two different networks, 192.168.0.0/24 and 192.168.1.0/24. Your System is in
192.168.0.0/24 Network. One RHEL 5 Installed System is going to use as a Router. All required
configuration is already done on Linux Server. Where 192.168.0.254 and 192.168.1.254 IP
Address are assigned on that Server. How will make successfully ping to 192.168.1.0/24
Network's Host?
Answer and Explanation:
1. vi /etc/sysconfig/network
GATEWAY=192.168.0.254
OR
vi /etc/sysconf/network-scripts/ifcfg-eth0
DEVICE=eth0
BOOTPROTO=static
ONBOOT=yes
IPADDR=192.168.0.?
NETMASK=255.255.255.0
GATEWAY=192.168.0.254
2. service network restart
15 CORRECT TEXT
Make a swap partition having 100MB. Make Automatically Usable at System Boot Time.
Answer and Explanation:
1. Use fdisk /dev/hda ¨¤ To create new partition.
2. Type n ¨¤ For New partition
3. It will ask for Logical or Primary Partitions. Press l for logical.
4. It will ask for the Starting Cylinder: Use the Default by pressing Enter Key.
5. Type the Size: +100M ¨¤ You can Specify either Last cylinder of Size here.
6. Press P to verify the partitions lists and remember the partitions name. Default System ID is 83
that means Linux Native.
7. Type t to change the System ID of partition.
8. Type Partition Number
9. Type 82 that means Linux Swap.
10. Press w to write on partitions table.
11. Either Reboot or use partprobe command.
12. mkswap /dev/hda?¨¤ To create Swap File system on partition.
13. swapon /dev/hda?¨¤ To enable the Swap space from partition.
14. free -m ¨¤ Verify Either Swap is enabled or not.
15. vi /etc/fstab
/dev/hda? swap swap defaults 0 0
16. Reboot the System and verify that swap is automatically enabled or not.
16.CORRECT TEXT
You are a System administrator. Using Log files very easy to monitor the system. Now there are 50
servers running as Mail, Web, Proxy, DNS services etc. You want to centralize the logs from allservers
into on LOG Server. How will you configure the LOG Server to accept logs from remote host ?
Answer and Explanation:
By Default system accept the logs only generated from local host. To accept the Log from otherhost
configure:
1. vi /etc/sysconfig/syslog
SYSLOGD_OPTIONS="-m 0 -r"
Where
-m 0 disables 'MARK' messages.
-r enables logging from remote machines
-x disables DNS lookups on messages recieved with -r
2. service syslog restart
17 CORRECT TEXT
You are giving the debug RHCT exam. The examiner told you that the password of root is redhat.
When you tried to login displays the error message and redisplayed the login screen. You
changed the root password, again unable to login as a root. How will you make Successfully Login as a
root.
Answer and Explanation:
When root unable to login into the system think:
1. Is password correct?
2. Is account expired?
3. Is terminal Blocked?
Do these Steps:Boot the System on Single user mode.Change the passwordCheck the account expire
date by using chage -l root command.
If account is expired, set net expire date: chage -E "NEVER" root
1. Check the file /etc/securetty ¨¤ Which file blocked to root login from certain terminal
2. If terminal is deleted or commented write new or uncomment.
3. Reboot the system and login as a root.

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NO.26 vi /etc/fstab

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NO.27 It will ask for the Starting Cylinder: Use the Default by pressing Enter Key.

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NO.28 CORRECT TEXT
There is one partition /dev/hda14 mounted on /data. The owner of /data is root user and root group. And
Permission is full to owner user, read and execute to group member and no permission to others. Now
you should give the full permission to user user1 without changing pervious permission.
Answer and Explanation:
We know that every files/directories are owned by certain user and group. And Permissions are defines to
owner user, owner group and other.
-rwxr-x--- ¨¤Full permission to owner user, read and write to owner group and no permission to
others.
According to question: We should give the full permission to user user1 without changing the previous
permission.
ACL (Access Control List), in ext3 file system we can give permission to certain user and certain group
without changing previous permission. But that partition should mount using acl option.
Follow the stepsvi /etc/fstab
/dev/hda14 /data ext3 defaults,acl 0 1Either Reboot or use: mount -o remount /datasetfacl -m
u:user1:rwx /dataVerify using: getfacl /data

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NO.29 Press w to write on partitions table.

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NO.30 CORRECT TEXT
Create the partition having 100MB size and mount it on /mnt/neo
Answer and Explanation:
1. Use fdisk /dev/hda ¨¤ To create new partition.
2. Type n ¨¤ For New partitions
3. It will ask for Logical or Primary Partitions. Press l for logical.

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